If you have 560 grams of magnesium. what mass of magnesium oxide will be produced?

=933.3 grams

Explanation:

Magnesium reacts with oxygen producing magnesium oxide according to the following equation.

2Mg₍s₎ + O₂₍g₎→ 2MgO₍s₎

From the above equation, 2 moles of Magnesium produces 2 moles of magnesium oxide. Therefore the ratio of magnesium to magnesium oxide produced is 1:1

1 mole of magnesium oxide has a mass of: 24+16 =40 grams

560 grams of magnesium=560/24 moles

=70/3 moles.

Since the ratio is 1:1 the reaction produces  70/3 moles of magnesium oxide.

70/3 moles of MgO= 70/3 moles× 40 grams

=933.3 grams

Here's what I get.

Explanation:

(d) Mass of chlorine

(i) We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:                  70.91      58.44

            2Na   +   Cl₂ ⟶ 2NaCl

m/g:                                   117

(ii) Calculate the moles of NaCl

(iii) Calculate the moles of Cl₂

The molar ratio is (1 mol Cl₂ /2 mol NaCl)

(iv) Calculate the mass of Cl₂