Asample of 9.27 g9.27 g of solid calcium hydroxide is added to 38.5 ml38.5 ml of 0.500 m0.500 m aqueous hydrochloric acid. write the balanced chemical equation for the reaction. physical states are optional. chemical equation: what is the limiting reactant? calcium hydroxide hydrochloric acid how many grams of salt are formed after the reaction is complete? mass of salt: gg how many grams of the excess reactant remain after the reaction is complete? excess reactant remaining:

HCl is a limiting reactant

mass of salt: 1.068375 g

8.559 g  of the excess reactant (Ca(OH)₂)remain after the reaction is complete

The reaction equation is the chemical formula of reagents and product substances

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products

Terms used:

Mole

The mole itself is the number of particles contained in a substance amounting to 6.02.10²³

We determine the mole of each reactant to determine the limiting reactant

then:

mol Ca (OH₂ = mass: molar mass

mole of Ca (OH)₂ = 9.27 g: 74

mole of Ca (OH)₂ = 0.1253

mole HCl: 38.5 ml x 0.5 M = 19.25 mlmol = 0.01925 mol

From the number of moles, it can be seen that HCl is a limiting reactant

Reaction:

                     Ca(OH)₂  +    2HCl         ⇒    CaCl₂      +         2H₂O

initial mole    0.1253         0.01925

reaction        0.009625   0.01925        0.009625           0.01925

remaining     0.115675       -                  0.009625           0.01925

Remaining unreacted Ca (OH)₂ mole: 0.115675

Amount of mass of CaCl₂ salt formed:

CaCl₂ mass = mole x molar mass

CaCl₂ mass = 0.009625 x 111

CaCl₂ mass = 1.068375

Remaining Ca(OH)₂ = 0.115675 x 74 = 8.559 g

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