Which terms could have a greatest common factor of 5m2n2? check all that apply. m5n55m4n310m4n15m2n224m3n4

The second and the third terms from the choices:

Explanation:

The greatest common factor of a set of numbers is found by:

         1) Write each number as a product of prime factors, each factor raised to the corresponding exponent (power);

         2) Choose only the common prime factors, with the least exponent.

Example: find the greatest common factor of 35x²y³ and 15xy²

                                         15xy² = 3¹ . 5¹ . x¹ . y²

Now apply the process to the given terms:

.

The terms that could have a greatest common factor of 5m²n², are those that include 5m²n², and those are:

These are the second and the third terms from the choices.

answer; /// i do believe that the correct answer is (c)nuclear bond

43.452

step-by-step explanation:

284 times .153 = 43.452