How much heat is released when 15.0 g of water vapor is condensed and then cooled from 100.0 c to -32.0 c? show work ❤️

46.85kJ

Explanation:

The specific latent heat of vaporization of water is =2.3 x 10⁶ J kg-1.

The specific heat capacity of water = 4.2×10³J/kgK

The latent heat of fusion of water= 3.36×10⁵ J/kg

The specific heat capacity of ice=2.108×10³ J/kgK

The heat of lost due to cooling of ice is calculated as follows by adding the heat lost during condensation of water vapor to the heat lost during cooling the water to freezing point plus the heat lost during freezing plus the heat lost during cooling the ice to -32.0°C

=MLv+MCΔT(water)+MLf+MCΔT(ice) where Lv=latent heat of vaporization of water , and Lf is the latent heat of fusion ice.

=(0.015kg×2.3 x 10⁶ J/kg)+(0.015kg×4.2×10³J/kgK×100K)+(0.015kg×3.36×10⁵ J/kg)+(0.015kg× 2.108×10³ J/kgK)×32K

=34500J+6300J+5040J+1011.84J

=46851.84J

=46.85kJ