In carbon monoxide, there is always 1.33 g of oxygen for every1g of carbon. how many grams of carbon are in a 16.03 gsample of carbon monoxide? carbon

There are 6.88 g of carbon in 16.03 g sample of carbon monoxide.

Carbon monoxide has formula as CO.

C => carbon

O => oxygen

From the question given above, we were told that there is always 1.33 g of oxygen for every 1 g of carbon. Thus,

O = 1.33C (1)

We were also told that the mass of CO is 16.03 g i.e

C + O = 16.03 (2)

O = 1.33C (1)

C + O = 16.03 (2)

From the equation above, we can obtained the mass of Carbon (C) as follow:

C + O = 16.03

O = 1.33C

C + 1.33C = 16.03

2.33C = 16.03

Divide both side by 2.33

C = 16.03 / 2.33

C = 6.88 g

Therefore, 16.03 g of the sample of carbon monoxide contains 6.88 g of carbon.

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given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"