If 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced? 4.0 mol 8.0 mol 16 mol 32 mol

32 mols of water

Explanation:

2H2 + O2 ==> 2H2O

What your givens are telling you and what the equation is saying is that

for every mol of O2, you get 2 mols of H2O

So you could do it with the proportion about.

1/16 = 2/x                 Cross multiply

x = 16 * 2

x = 32

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.