25.0 ml of 0.212 m naoh is neutralized by 13.6 ml of an hcl solution. the molarity of the naoh solution is

Molarity of NaOH = 0.212M, Molarity of HCl = 0.436M

Explanation:

Before answering the question, it is crucial to write out the chemical equation between HCl and NaOH. This is given below as;

HCl + NaOH -> NaCl + H2O

HCl is the Acid and NaOH is the base.

From the reaction we can tell that 1 mole of HCl reacts with 1 mole of NaOH.

We use the acid base relationship in calculating unknown concentration;

The question stated the following;

Volume of NaOH (Vb) = 25.0ml

Concentration of NaOH (Cb) = 0.212M

Volume of HCl (Va) = 13.6ml

Concentration of HCl (Ca) = ?

From the equation above;

Na = 1

Nb = 1

Cb = (1 * 0.212 * 25) / (13.6 * 1)

Cb = 0.436 M

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