Asample of hydrated copper (ii) sulfate has a mass of 4.56 g. after heating, it has a mass of 2.92 g. what is the percent by mass of water in the hydrate?

36.0%.

Explanation:

The mass of water = mass of hydrated copper (II) sulfate - mass of copper (II) sulfate after heating = 4.56 g - 2.92 g = 1.64 g.

The percent by mass of water in the hydrate = (mass of water/mass of hydrated copper (II) sulfate)*100 = (1.64 g/4.56 g)*100 = 35.96% ≅ 36.0%.

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.