The solubility of nitrogen gas at 25 degrees c and 1 atm is 6.8 x 10^(-4) mol/l. if the partial pressure of nitrogen gas in air is 0.76 atm, what is the concentration (molarity) of dissolved nitrogen? 5.2 x 10^(-4) m 1.1 x 10^(-5) m 4.9 x 10^(-4) m 3.8 x 10^(-4) m 6.8 x 10^(-4) m

5.2 x 10⁻⁴ M.

Explanation:

P = kC

where P is the partial pressure of the gaseous  solute above the solution.

k is a constant (Henry’s constant).

C is the concentration of the dissolved gas.

P₁C₂ = P₂C₁,

P₁ = 1.0 atm, C₁ = 6.8 x 10⁻⁴ mol/L.

P₂ = 0.76 atm, C₂ = ??? mol/L.

∴ C₂ = (P₂C₁)/P₁ = (0.76 atm)(6.8 x 10⁻⁴ mol/L)/(1.0 atm) = 5.168 x 10⁻⁴ mol/L ≅ 5.2 x 10⁻⁴ M.

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