During a laboratory experiment, 44.18 grams of al2o3 was formed when o2 reacted with aluminum metal at 290.0 k and 1.3 atm. what was the volume of o2 used during the experiment? 3o2 + 4al → 2al2o3 a. 10.10 liters b. 11.90 liters c. 12.51 liters d. 15.55 liters

The correct answer is option B.

Explanation:

Mass of = 44.18 g

Moles of

According to reaction , 2 moles of is formed from 3 moles of oxygen.

Then from 0.4331 moles of moles of oxygen gas formed will be:

In order to find the volume of the oxygen gas we will use ideal gas equation:

Hence, the correct answer is option B.

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