To ensure that the air in the shuttle remains free of excess co2, engineers test the air-purification system. they combine 1.000 × 103 g lioh with 8.80 × 1 02 g co2. the reaction produces 3.25 × 102 g h2o. what is the limiting reactants in this test reaction? what is the theoretical yield of this test reaction?

The

balanced reaction is:

2LiOH + CO2 = Li2CO3 + H2O

We

are given the amount of the reactants to be reacted. This will be the starting point of our

calculations. To determine the limiting reactant, we convert the amounts from grams to moles.

1.000 × 10^3 g LiOH  (1 mol / 25.95 g) = 38.54 mol LiOH

8.80 × 10^2 g CO2 ( 1mol / 44.01 g) = 20.00 mol CO2

From the balanced reaction, the molar ratio of the reactants is 2:1. This means that every two mole of lithium hydroxide, 1 mole of carbon dioxide is needed. It is clear that, from the given amounts, CO2 is the limiting reactant.