You have a cup of tea (250 ml) that is 375 k which is too hot to drink. it needs to be cooled to 350 k before you can drink it. how much thermal energy has to be transferred from the tea to the surroundings to cool the tea? show all work and include units.

The hot tea should transfer 25.63 kJ the surroundings to cool the tea.

Explanation:

Q = m.c.ΔT,

where, Q is the amount of heat has to be transferred from the tea to the surroundings to cool the tea (Q = ??? J).

m is the mass of the hot tea (m = dV = (1.0 g/mL)(250 mL) = 250 g), suppose the density of water is the density of tea.

c is the specific heat of the hot tea (c = 4.10 J/°C.g).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 350 K - 375 K = -25°C).

∴ Q = m.c.ΔT = (250 g)(4.10 J/°C.g)(-25°C)) = - 25630 J = - 25.63 kJ.

So, the hot tea should transfer 25.63 kJ the surroundings to cool the tea.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.