An expandable container of oxygen gas has a volume of 125 ml and a temperature of 25.0ºc. what volume will the gas occupy at 55°c?

148.1 mL.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

(V₁T₂) = (V₂T₁)

V₁ = 125 mL, T₁ = 25°C + 273 = 298 K,

V₂ = ??? mL, T₂ = 55°C + 273 = 353 K,

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂)/(T₁) = (125 mL)(353 K)/(298 K) = 148.1 mL.

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