In the reaction of sodium with bromine, explain which atom is reduced.

i need you to show all the steps because i don't understand.

The reduced atom is Br.

Explanation:

2Na + Br₂ → 2NaBr,

Na loses 1 electrons and is oxidized to Na⁺. (Na → Na⁺ + e).

Br₂ gains 2 electrons and is reduced to 2Br⁻. (Br₂ + 2e → 2Br⁻).

So, the reduced atom is Br.

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