What is the molarity of a solution that contains 0.202 mol kci in 7.98 l solution?

0.02531 M ≅ 0.025 M.

Explanation:

Molarity (M) is the no. of moles of solute that dissolved in 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L).

∴ M of KCl = (no. of moles of solute)/(V of the solution (L) = (0.202 mol)/(7.98 L) = (500.0 g/46.4 g/mol)/(4.44 L) = 0.02531 M ≅ 0.025 M.