In the haber reaction, patented by german chemist fritz haber in 1908, dinitrogen gas combines with dihydrogen gas to produce gaseous ammonia. this reaction is now the first step taken to make most of the world's fertilizer. suppose a chemical engineer studying a new catalyst for the haber reaction finds that 284. liters per second of dinitrogen are consumed when the reaction is run at 196.°c and 0.75atm . calculate the rate at which ammonia is being produced. give your answer in kilograms per second. be sure your answer has the correct number of significant digits.

Explanation:

1) Word equation (given):

•Dinitrogen gas + dihydrogen gas → gaseous ammonia.

2) Chemical equation:

•N₂ (g) + 3H₂ (g) → 2NH₃ (g)

3) Mole ratios:

•1 mole N₂ (g) : 3 mole H₂ (g) : 2 mole NH₃ (g)

4) Reaction rates:

•Rate of dinitrogen consumption: r₁ = n₁ / t (moles/s)

•Rate of ammonia production: r₂ = n₂ / t (moles/s)

•Due to the stoichiometric ratios: r₂ = 2 × r₁

5) Calculate r₁:

•284 liter / s

•PV = nRT ⇒ n = PV / (RT)

•Divide by time, t: n/t = P (V/t) / (RT)

•Substitute V/t = 284 liter/s, P = 0.75 atm, and T = 196 +273.15K = 469.15K

r₁ = n₁ / t = (0.75 atm) (284 liter/s) / [ (0.08206 atm-liter/K-mol) (469.15k) ]

= 5.53 moles/s

6) Calcualte r₂

7) Convert rate in mole/s to rate in kg/s

the answer is b & c i believe : )

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole