The initial temperature of a bomb calorimeter is 28.50°c. when a chemist carries out a reaction in this calorimeter, its temperature decreases to 27.45°c. if the calorimeter has a mass of 1.400 kg and a specific heat of 3.52 j/(gi°c), how much heat is absorbed by the reaction? use . 140 j 418 j 1,470 j 5,170 j

5,170 J.

Explanation:

Q = m.c.ΔT.

where, Q is the amount of heat released from the calorimeter (Q = ??? J),

m is the mass of the calorimeter (m = 1.4 kg = 1400.0 g),

c is the specific heat capacity of the calorimeter (c = 3.52 J/g °C),

ΔT is the temperature difference (final T - initial T) (ΔT = 27.45 - 28.50 = - 1.05°C).

∵ Q = m.c.ΔT.

∴ Q = m.c.ΔT = (1400.0 g)(3.52 J/g °C)(- 1.05°C) = - 5174.0 J ≅ - 5,170 J.

∴  The amount of heat absorbed by the reaction = 5,170 J.

it is stable as it is in group 0 which have full outer shells of electrons