If 10.0 l of oxygen gas at stp are heated to 512 celsius what will be the new volume of the gas if the pressure is also increased to 1.75 atm?

16.4 L

Explanation:

we can use the combined gas law equation that gives the relationship among volume, temperature and pressure conditions of gases.

P1V1/T1 = P2V2/T2

STP conditions are standard temperature and pressure conditions

P1 is standard pressure = 1 atm , T1 is standard temperature = 273 K

and V1 is the volume

P2 is pressure, T2 is temperature and V2 is volume at the second instance

temperature is in kelvin scale,

512 ° + 273 = 785 K

substituting the values in the equation

1 atm x 10.0 L / 273 K = 1.75 atm x V / 785 K

V = 16.4 L

new volume is 16.4 L

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.