What is the molarity of a solution prepared by dissolving 10.0 grams of naoh in enough water to make a solution with a total volume of 2.40 liters?

0.104 m naoh
0.201 m naoh
0.361 m naoh
0.412 m naoh

0.104 M NaOH

Explanation:

molarity or concentration is the number of moles of solute dissolved in 1 L of solution

the mass of NaOH dissolved is 10.0 g

therefore number of moles of NaOH is - 10.0 g / 40 g/mol = 0.25 mol

molarity/concentration = number of moles of solute / volume of solution

substituting the values in the equation = 0.25 mol / 2.40 L = 0.104 mol/L

therefore molarity of NaOH is 0.104 M

=0.104 M of NaOH

Explanation:

NaOH=23+16+1=40

40=1 M

10=? And the answer is 0.25

0.25=2400

  ?    =1000

1000*0.25/2400=0.104

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.