What can be said about an endothermic reaction with a negative entropy change? spontaneous at all temperatures. spontaneous at high temperatures. spontaneous at low temperatures. spontaneous in the reverse direction at all temperatures. nonspontaneous in either direction at all temperatures. submit

Explanation:

The parameter to predict the spontaneity of a reduction is the change in the free energy, ΔG.

This is how it works:

In brief, free energy's decrease tells that a reaction is spontaneous, while free energy's increase tells a reaction is nonspontaneous.

Now, take the definition of the free energy:

The conditions given in the statement are:

Replacing in the equation ΔG = ΔH - TΔS, you get:

Then, you conclude that for an endothermic reaction with a negative entropy change, the change in the free energy is positive, and so the reaction is nonspontaneous (at all temperatures) in the forward direction.

Since, the change in the reverse direction has opposite sign, you also conclude that the reaction is spontaneous in the reverse direction at all temperatures.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

2b2t

explanation:

2b2t