Citric acid (h3 c6 h5 o7) is a product of the fermentation of sucrose (c12 h22 o11) in air.

c12 h22 o11(aq) + 3 o2(g) yields 2 h3 c6 h5 o7(aq) + 3 h2 o

determine the mass of citric acid produced when 2.50 mol c12 h22 o11 is used.

show all the steps you took to get the answer!

960.6175

Explanation:

The balanced equation shows that for every mole of sucrose used, 2 moles of  citric acid are produced.

So 2.5 moles of C12H22O11 will produce 2*2.5 moles of Citric acid.

So 2.5 moles of C23H22O11 will produce 5 moles of Citric Acid.

The next step is to figure out the molar mass of Citric Acid.

There are

Hydrogen: H3 + H5 moles of hydrogen in 1 mole of Citric Acid = 8 mol H

Carbon: 1 mol of Citric Acid has 6 moles of Carbon in it             = 6 mol C

Oxygen: 1 mol of Citric Acid has 7 moles of Oxygen it it              =7 mol O

Hydrogen has  a mass of 1  so Citric Acid has 1 * 8 grams H          8

Carbon has a mass of 12 so Citric Acid has 12 * 6 grams C           72

Oxygen has a mass of 16 so Citric Acid has 16 * 7 grams O          112

Total grams for 1 mol Citric Acid                                                     192    

The official published mass of Citric Acid is 192.1235 so because I used rounded numbers I'm a little off. It is important for any chemistry student student to know  where the 192.1235 came from rather than exactly why I'm a little out. Every periodic table lists different masses for each element. If you want a better number, you will have to consult your own periodic table.

1 mol of Citric Acid = 192 grams

5 mols of Citric Acid = x

Cross multiply

1 * x = 5 * 192

x = 960 grams.

If you want to use the published amount then the answer will be 5 * 192.1235 = 960.6175

fdvwsa gfwsargebgeebbfwfwffw gwf   vgwgw gw f gwgw fgw v v dsv dwfff

so what is the problem with your lab report and whats the subject of the lab report? i will you