What is the molarity of a 2.0 l sodium hydroxide solution containing 10.0 grams of solute?

0.125 M

Explanation:

Molarity or concentration is given by;

= Moles/volume in litres

But; moles = mass/Relative formula mass

                  = 10.0/40.0

                  = 0.25 Moles

Molarity = 0.25 moles/2.0 L

              = 0.125 M

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o

the correct answer would be b) volume versus temperature, because they are also directly proportional.