If there are 50 grams of u-238 on day zero of radioactive decay, how much will there be after 4.5 billion years? a) 0.0 grams b) 10 grams c) 25 grams d) 50 grams

= 25 g

Explanation:

Using the formula;

A = A₀ (1/2)^(t/h)

where A is the final amount,

A₀ is the initial amount of the substance,

t is the time and

h is the half-life of the substance,

In this case; the half life of U-238 h is equal to 4.47 billion years.

A = A₀ (1/2)^(t/h)

A = 50 (1/2)^(4.5 / 4.47)

   = 24.88

  = 25 g

c. orbital shape i hope this is correct