Write the balanced combustion equation for solid barium. remember that combustion is a type of synthesis reaction.
2ba + o2 ➡ 2bao
ba + o ➡ bao
2ba + o ➡ ba2o
2ba + o2 ➡ ba2o2

2Ba + O2 --> BaO

Explanation:

A combustion reaction is a reaction between a fuel with oxygen. Is this case, the fuel is Barium, which is a metal of group 2A, so it has 2 electrons in its valence shell. It must donate these 2 electrons to be stable and will be the cation .

Oxygen is in group 6A, so it has 6 electrons in its valence shell, so must gain 2 electrons to be stable, and will be the anion . So, they will form an ionic compound, and we need to change their charges without the signal to form its formula:

Ba2O2 = BaO

The reaction is:

Ba + O2 --> BaO

Balancing:

2Ba + O2 --> 2BaO

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.