How many moles of sodium chloride (nacl) solute are in 205 grams of a 92.5 percent by mass solution? (3 points) 2.63 mol nacl 3.24 mol nacl 7.71 mol nacl 1.92 mol nacl

The correct answer would be: 3.24 mol NaCl

I hope that this helps you !

3.24

Explanation:

you simply divide 205 by the periodic table mass of both elements combined (35.453+22.99). This comes out to be 205/58.443, which is 3.50769. Then, multiply this by 0.925 and you get a figure around 3.24

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

c. 75.7

i think that is the right