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Chemistry, 19.10.2019 23:30 Carlyalexis77301
1.) rust forms when fe, o₂, and h₂o react in the balanced equation below;
2fe(s) + o₂(g) +2h₂o(l) --> 2fe(oh)₂(s)
in an experiment 10.0g of fe is allowed to react with 4.00g of o₂
a.) which of these reactants is the limiting reagent?
b.) how many grams of fe(oh)₂ are formed?
2.) (using the reaction listed in question 1.) if 2.00g fe is reacted with an excess of o₂ and h₂0, and a total of 2.74g of fe(oh)₂ is actually obtained, what is the % yield?
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1.) rust forms when fe, o₂, and h₂o react in the balanced equation below;
2fe(s) + o₂(g)...
2fe(s) + o₂(g)...
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