How many liters of 4.0 m naoh solution will react with 0.60 liters 3.0 m h2so4?
h2so4 + naoh —> na2so4 + h2o
a. 0.90 l
b. 1.0 l
c. 1.1 l
d. 2.1 l

A. 0.90 L.

Explanation:

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.

1.0 mole of H₂SO₄ reacts with 2.0 moles of NaOH.

∴ (MV) NaOH = (xMV) H₂SO₄.

x for H₂SO₄ = 2, due to having to reproducible H⁺ ions.

∴ V of NaOH = (xMV) H₂SO₄/ M of NaOH = 2(0.6 L)(3.0 M)/(4.0 M) = 0.90 L.

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