Write a balanced equation for the decomposition of naalh4.

2 NaAlH₄ (s)  →  2 NaH (s) + 2 Al (s) + 3 H₂(g)

Explanation:

Decomposition reaction -

It is the type of reaction , where one only one reactant and more than one products ,

As, the reactant breaks down into two or more than products , the reaction me use some sort of catalyst or with the aid of heat and light to proceed , is known as a decomposition reaction .

The decomposition of NaAlH₄ , can be done in the following manner -

generating , NaH and Al  as the solid product and H₂ as the gaseous product,

NaAlH₄ (s)  →  NaH (s) +  Al (s) +  H₂(g)

The reaction can be balanced , simply by equalizing in the number of atoms in the reactant with the number of atoms in the product side , by multiplying the molecule with whole numbers .

Hence , the balanced reaction is given as -

2 NaAlH₄ (s)  →  2 NaH (s) + 2 Al (s) + 3 H₂(g)

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

answer; /// i do believe that the correct answer is (a) boiling