What is the molar concentration of the acid if 35.18 ml of hydrochloric acid was required to neutralize 0.745 g of aluminum hydroxide?

The mass number of aluminium hydroxide is 78 thus, the number of moles in 0.745 g is:

no. of moles= mass/ RFM

= 0.745/78

=0.00955moles

Therefore the 0.00955 moles should be in the 35.18 ml

therefore 1000ml of the solution will have:

(0.00955ml×1000ml)/35.18

=0.2715moles

The  solution will be 0.27M hydrochloric acid  

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a:

by the combination of an unlimited number of elements