To what volume must 480.0 ml of 3.50 m cu(no3)2 be diluted to produce 2.10 m cu(no3)2?

800 mL

Explanation:

This is a dilution question so we have to use the dilution formula

c1v1 = c2v2

Where c1 is the concentration and v1 is the volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

Substituting the values in the equation

3.50 M x 480.0 mL = 2.10 M x v2

v2 = 800 mL

A volume of 480.0 mL of 3.50 M solution should be diluted upto a volume of 800 mL to make a diluted copper nitrate solution of concentration 2.10 M

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.