When a mercury-202 nucleus is bombarded with a neutron, a proton is ejected. what element is formed?

That will make a gold-202 nucleus.

Refer to a periodic table. The atomic number of mercury Hg is 80.

Step One: Bombard the with a neutron . The neutron will add 1 to the mass number 202 of . However, the atomic number will stay the same.

.

Double check the equation:

Step Two: The nucleus loses a proton . Both the mass number 203 and the atomic number will decrease by 1.

Refer to a periodic table. What's the element with atomic number 79? Gold Au.

.

Double check the equation:

A gold-202 nucleus is formed.

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

i would say b

explanation:

but i think i would need more information than that