Calculate the molarity of a solution in which 212.5g of nano3 are contained in 3.0 liters of solution.

Molarity's formula is: moles solute/liters solution.

In this question, we are given grams of solute so we have to convert that to moles.

NaNO3 has a molar mass of 84.9947g/mol. Here we begin with the given 212.5g and multiplying it by 1mol/84.9947g because the grams have to cancel out to give moles.

Now that we have moles of solute, we just plug it into the formula.

2.5 mols NaNO3/3L solution=0.8333 M of solution

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i  

10 years is the answer