Answers: 2
ions in the solution is 
.![pH=-\log[H^+]](/tpl/images/0420/1187/cf945.png)
![3.75=-\log[H^+]](/tpl/images/0420/1187/128bb.png)
![[H^+]=Antilog [-3.75]=0.0001778=1.778\times 10^{-4} M](/tpl/images/0420/1187/24cf9.png)
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Achemist is using a solution of hno3 that has a ph of 3.75. what is [h+] for the solution? 1.78 ร 1...
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