What is the solubility, in moles/liter, of pbcl2 if the ksp =7.3 x 10^12

Ksp=[Pb][Cl]²
since we know that for every atom of Pb in solution, there are 2 atoms of Cl.  That means if we set [Pb]=x, [Cl]=2x and we can rewrite the Ksp equation as Ksp=x4x² and then you can solve for x to find the [Pb] in the solution.  Since there is 1 mole of Pb in 1 mol of PbCl₂, and the units of molarity is moles/L, we can say that the concentration of Pb in the solution is equal to the solubility of PbCl₂.

7.3x10^12=4x³
x³=1.825x10^12
x=12220M
Therefore the solubility of PbCl₂ is 12220 moles/liter

This works since Ksp is referring to the maximum amount of solute that can dissolve in the solution and is therefore directly related to how soluble a compound is.  The bigger the Ksp is , the more soluble it is.

I hope this helps.

The angle of reflection is 30°

Answer:

5.6⋅10−^19  j

do you need the explaination?