In an experiment, zinc chlorate decomposed according to the following chemical equation.

zn(clo3)2 → zncl2 + o2

(molar mass of zn(clo3)2 = 232.29 g/mol; zncl2 = 136.286 g/mol; o2 = 31.998 g/mol)

if the mass of zinc chlorate was 150 grams, which of the following calculations can be used to determine the mass of oxygen gas formed?

(150 × 1 × 232.29) ÷ (31.998 × 3) grams
(150 × 3 × 232.29) ÷ (31.998 × 1) grams
(150 × 1 × 31.998) ÷ (232.29 × 3) grams
(150 × 3 × 31.998) ÷ (232.29 × 1) grams

Answer : The correct expression is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Explanation :

First we have to calculate the moles of

Now we have to calculate the moles of

The balanced chemical reaction is,

From the balanced chemical reaction we conclude that,

As, 1 mole of react to give 3 mole of

So, moles of react to give moles of

Now we have to calculate the mass of

Therefore, the correct expression for the mass of oxygen gas formed is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Answer : The correct expression is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Explanation :

First we have to calculate the moles of

Now we have to calculate the moles of

The balanced chemical reaction is,

From the balanced chemical reaction we conclude that,

As, 1 mole of react to give 3 mole of

So, moles of react to give moles of

Now we have to calculate the mass of

Therefore, the correct expression for the mass of oxygen gas formed is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

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