Asolution is made by dissolving 23.5 grams of glucose (c6h12o6) in 0.245 kilograms of water. if the molal freezing point constant for water (kf) is -1.86 °c/m, what is the resulting δf of the solution? show all the steps taken to solve this problem. (4 points)

- 0.99 °C ≅ - 1.0 °C.

Explanation:

ΔTf = (Kf)(m),

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

m is the molality of the solution (m = moles of solute / kg of solvent = (23.5 g / 180.156 g/mol)/(0.245 kg) = 0.53 m.

∴ ΔTf = (Kf)(m) = (-1.86 °C/m)(0.53 m) = - 0.99 °C ≅ - 1.0 °C.

the answer is a and have a great day

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