(thermodynamics)

how much energy is released when 56.0 of h_2so_4 (98.1) react with excess lioh?

65.8 kJ  

Step-by-step explanation:

M_r:    98.1

         H₂SO₄ + 2LiOH ⟶ Li₂SO₄ + 2H₂O

The net ionic reaction is

H₃O⁺ + OH⁻ ⟶ 2H₂O; ΔH = -57.62 kJ·mol⁻¹

1. Calculate the moles of H₂SO₄

Moles of H₂SO₄ = 56.0 g H₂SO₄ × (98.1 g H₂SO₄/1 mol H₂SO₄)

= 0.5708 mol H₂SO₄

2. Calculate the moles of H₃O⁺

H₂SO₄ + 2H₂O ⟶ 2H₃O⁺ + SO₄²⁻

Moles of H₃O⁺ = 0.5708 mol H₂SO₄ × (2 mol H₃O⁺/1 mol H₂SO₄)

= 1.142 mol H₃O⁺

3. Calculate the energy released

q = 1.142 mol H₃O⁺ × (-57.62kJ/1 mol H₃O⁺) = -65.8 kJ

The neutralization releases 65.8 kJ.

gasoline is a mixture. it contains several different kinds of compounds that can be present in a variety of ratios.