Calculate the resulting ph obtained by mixing 16.5 g hcl and 22.6 g nacl in water to create 482 l solution.

pH = 3.03

NaCl is a neutral salt and does not affect the pH.  

moles HCl = g HCl / MM

                  = 16.5 / 36.5

                  = 0.452 equivalent to moles H+  

Molarity H+ = moles H+ / L

                   = 0.452 / 482

                   = 0.000938 M  

Hence; pH = -log[H+]

                  = -log(0.000938)

                  = 3.03

am i too late?

explanation:

the answer is b & c i believe : )