You have 25.0ml hcl of unknown concentration. it takes 12.5 ml of 0.2 m naoh to neutralize the acid. determine the concentration of hcl in the following steps.

which data table would you use to organize the information correctly?

1) The concentration of HCl = 0.1 M.

2) The table that can be used to organize the information correctly is C.

Explanation:

1) The concentration of HCl:

which means that: (MV)HCl = (MV)NaOH,

M of HCl = ??? M, V of HCl = 25.0 mL.

M of NaOH = 0.2 M, V of NaOH = 12.5 mL.

∴ M of HCl = (MV)NaOH/V of HCl = (0.2 M)(12.5 mL)/(25.0 mL) = 0.1 M.

2) The table that can be used to organize the information correctly is C

Table A and B are the same and reported volume of HCl and NaOH is wrong.

Table C is right, contain the correct volumes and concentration of NaOH and missed the concentration of HCl which is 0.1 M.

Table D reported the volume and the concentration of HCl wrongly and also the concentration of NaOH. The data reported of HCl and NaOH is reversed.

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error

answer: i dont know the answer but this might

explanation:

l