Four substances at the same temperature absorb equal amounts of energy. the specific heats of the four substances are 1.01 j/g °c, 0.38 j/g °c, 0.45 j/g °c, and 2.00 j/g °c. what is the specific heat value of the substance that will have least increase in temperature? 0.38 j/g °c 0.45 j/g °c 1.01 j/g °c 2.00 j/g °c

2.00 J/g.°C

Explanation:

To solve this problem, we can use the relation:

Q = mcΔT,

Where, Q is the amount of heat needed to raise the temperature of the substance (J).

m is the mass of the substance (g).

c is the specific heat capacity of the substance (J/g.°C).

ΔT is the temperature difference (ΔT = final T - initial T).

As clear from the relation; ΔT = Q / mc,

∵ ΔT ∝ 1/c,

The temperature difference is inversely proportional to the specific heat of the substance.

∴ The substance that will have least increase in temperature will be that has the highest specific heat capacity (2.00 J/g.°C).

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while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.