Stoichiometry and gases, explain]

the following reaction takes place at stp. 4.40 l of nitrogen gas are formed. how many grams of ammonium nitrite decomposed?

2 nh4no2 (aq) > 2 n2 (g) + 4 h2o (l)

The mass of ammonium nitrite decomposed is 12.54 grams.

Explanation:

Pressure of the nitrogen gas = P = 1 atm

Volume of the nitrogen gas = V = 4.40 L

Temperature of the nitrogen gas = T = 273.15 K

Moles of nitrogen gas = n

PV = nRT (ideal gas equation)

According to reaction , 2 mole of nitrogen is obtained from 2 mole of ammonium nitrite.

Then 0.196 moles of nitrogen will  will be obtained from:

ammonium nitrite.

Mass of 0.196 moles of ammonium nitrite:

= 0.196 mol × 64 g/mol = 12.54 g

The mass of ammonium nitrite decomposed is 12.54 grams.

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