[15 points, stoichiometry and gases]

find the grams of cac2 (@ 1.25 atm, 385 k and c2h2 has 550 l)

cac2 (s) + 2 h2o (l) > ca(oh)2 (s) + c2h2 (g)

The mass of calcium carbide is 1,392 grams.

Explanation:

Pressure of the ethyne gas = P = 1.25 atm

Volume of the ethyne gas = V = 550 L

Temperature of the ethyne gas = T = 385 K

Moles of ethyne gas = n

PV = nRT (ideal gas equation)

According to reaction , 1 mole of ethyne is obtained from 1 mole of calcium carbide.

Then 21.75 moles of ethyne will be obtained from:

calcium carbide.

Mass of 21.75 moles of calcium carbide:

= 21.75 mol × 64 g/mol = 1,392 g

The mass of calcium carbide is 1,392 grams.

idk what the question is about

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.