Iron(ii) chloride and sodium carbonate react to make iron(ii) carbonate and sodium chloride: fecl2(aq) + na2co3(s) → feco3(s) + 2nacl(aq). given 1.24 liters of a 2.00 m solution of iron(ii) chloride and unlimited sodium carbonate, how many grams of iron(ii) carbonate can the reaction produce?

287.32 g.

Explanation:

The balanced equation of the reaction is:

FeCl₂ + Na₂CO₃ → FeCO₃ + 2NaCl.

It is clear that 1.0 mole of FeCl₂ reacts with 1.0 mole of Na₂CO₃ to produce 1.0 mole of FeCO₃ and 2.0 moles of NaCl.The limiting reactant is FeCl₂ and Na₂CO₃ is an unlimited reactant.We can calculate the no. of moles of FeCl₂ using the data available:

M = 2.0 mol/L and V = 1.24 L.

∴ n of FeCl₂ = M x V = (2.0 mol/L)(1.24 L) = 2.48 mol.

Using cross multiplication; we can calculate the no. of moles of  iron(II) carbonate can the reaction produce:

1.0 mole of FeCl₂ produces → 1.0 mole of FeCO₃, from the stichiometry.

2.48 moles of FeCl₂ produces → ??? mole of FeCO₃.

The no. of moles of  iron(II) carbonate can the reaction produce = (1.0 mol)(2.48 mol) / (1.0 mol) = 2.48 mol.Now, we can calculate the grams (mass) of iron(II) carbonate can the reaction produce = n x molar mass = (2.48 mol)(115.854 g/mol) = 287.32 g.

Okay well gravitational energy is matter forced by gravity making energy though the kinetic energy then the electric energy produces electricity from the kinetic energy and the kinetic energy gets its energy from the gravitational energy. was that the answer you wanted or something else?  

☆ionisation energy increases across a period from na -> ar☆ionisation energy decreases down a group from li -> fr☆ionic radius decreases across a period from na -> cl☆ionic radius increases down a groupfrom f -> ii hope it clarifies your doubts