The following reaction shows calcium chloride reacting with silver nitrate
cacl2 + agno3 —>
agcl + ca(no3)2
how many grams of agcl are produced from 30.0 grams of cacl2?
ca = 40.078, cl = 35.453,
o = 15.999, ag = 107.868,
n = 14.007

a. 19.0
b. 38.8
c. 58.2
d. 77.5

D. 77.5.

Explanation:

Using cross multiplication:

1.0 mole of CaCl₂ produces → 2.0 moles of AgCl, from the stichiometry.

0.27 mol of CaCl₂ produces → ??? moles of AgCl.

∴ The no. of moles of the produced AgCl = (2.0 mol)(0.27 mol) / (1.0 mol) = 0.54 mol.

∴ The mass of the produced AgCl = no. of moles x molar mass = (0.54 mol)(143.32 g/mol) = 77.48 g ≅ 77.5 g.

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