The following reaction shows calcium chloride reacting with silver nitrate
cacl2 + agno3 —>
agcl + ca(no3)2
how many grams of agcl are produced from 30.0 grams of cacl2?
ca = 40.078, cl = 35.453,
o = 15.999, ag = 107.868,
n = 14.007

a. 19.0
b. 38.8
c. 58.2
d. 77.5

D. 77.5.

Explanation:

Using cross multiplication:

1.0 mole of CaCl₂ produces → 2.0 moles of AgCl, from the stichiometry.

0.27 mol of CaCl₂ produces → ??? moles of AgCl.

∴ The no. of moles of the produced AgCl = (2.0 mol)(0.27 mol) / (1.0 mol) = 0.54 mol.

∴ The mass of the produced AgCl = no. of moles x molar mass = (0.54 mol)(143.32 g/mol) = 77.48 g ≅ 77.5 g.

58750.08068 is the answer i think

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error