The rate constant (k) for a reaction was measured as a function of temperature. a plot of lnk versus 1/t(in k) is linear and has a slope of −9.20×103 k . you may want to reference (pages 642 - 648) section 14.5 while completing this problem. part a calculate the activation energy for the reaction.

The Arrhenius equation is

so if we plot a graph between lnK (natural log of rate constant) and 1/T (inverse of temperature in kelvin)

The straight line equation will be

lnK = lnA - Ea/RT

Where

A = constant for a particular reaction at any temperature

R = gas constant = 8.314 J /molK

So as per this equation the slope of line will be = -Ea/R

Or

Ea = -slope X R

Ea = -(-9.20X10³X 8.314) =76.49kJ /mol

activation energy = 76.49 kJ /mol

c is the answer because when something is left after something evaporates that shows the chemical change.

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation: