How many grams of water are needed to react with 485g of cac2

273 g  

Step-by-step explanation:

a) Balanced equation

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:    64.10   18.02

          CaC₂ + 2H₂O ⟶ Ca(OH)₂ + 2C₂H₂

m/g:    485

(b) Mass of H₂O

(i) Calculate the moles of CaC₂

n = 485 g CaC₂ × (1 mol CaC₂/64.10 g CaC₂)

  = 7.566 mol CaC₂  

(ii) Calculate the moles of H₂O

The molar ratio is (2 mol H₂O /1 mol CaC₂)

n = 2.00 mol CaC₂ × (7.566 mol H₂O /1 mol CaC₂)

  = 15.13 mol H₂O

(iii) Calculate the mass of H₂O

m = 165.16 mol H₂O × (18.02 g H₂O /1 mol H₂O)

    = 273 g H₂O

The reaction requires 273 g H₂O.

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation: