If 0.905 mol al2o3 is produced in the reaction, what mass of fe in product's

Amount of iron produced is 101.36 grams.

Explanation:

For the reaction of aluminium and iron oxide, the equation follows:

By Stoichiometry of the reaction,

When 1 mole of aluminium oxide is produced, then 2 moles of iron is also produced.

So, when 0.905 moles of aluminium oxide is produced, then of iron is also produced.

Now, to calculate the amount of iron produced, we use the equation:

Molar mass of iron = 56 g/mol

Moles of iron = 1.81 moles

Putting values in above equation, we get:

Hence, amount of iron produced is 101.36 grams.

58750.08068 is the answer i think