What volume of carbon monoxide will contain 3.02x10^23 molecules?

11.23 L.

Explanation:

Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).

Using cross multiplication:

1.0 mole → 6.022 x 10²³ molecules.

??? mole → 3.02 x 10²³ molecules.

The no. of moles of CO = (3.02 x 10²³ molecules) (1.0 mole) / (6.022 x 10²³ molecules) = 0.5 mol.We can calculate the volume of knowing that 1.0 mole of a gas at STP occupies 22.4 L.

Using cross multiplication:

1.0 mole of CO occupies → 22.4 L.

0.5 mole of CO occupies → ??? L.

∴ The volume of CO contain 3.02 x 10²³ molecules = (22.4 L)(0.5 mole) / (1.0 mole) = 11.23 L.

C. definite shape, definite volume. that is a solid.

It is a mixture. simply put, a compound must be pure, that is, of only one chemical structure and composition. a mixture is made of different chemical substances (i.e. elements, molecules, compounds) that are not chemically bonded to each other, but instead physically grouped together, as in the case of gasoline (a homogeneous solution).