Find the mass in grams of hydrogen gas produced when 14.0 moles of hcl is added to an excess amount of magnesium.

14.0 g of hydrogen gas

The equation for the reaction is

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)  

From the equation, 2mol HCl will produce 1 mol H2

Moles of HCl =14 moles

Therefore; 14 moles of HCl will produce 7 moles of hydrogen gas

1 mole of Hydrogen gas = 2.0 g/mol

Thus; mass of 7.0 moles of H2 = 7 × 2.0 g/mol

                                                   = 14.0 g

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error

explanation:

0.07 g/cm³

1.37 g/cm³