Calculate the change in entropy if br2(l) is converted to br2(g). s° for br2(l) = 152.2 j/(mol•k) s° for br2(g) = 245.5 j/(mol•k) s° for br(g) = 175.0 j/(mol•k)

Ans: The entropy change for the given reaction is 93.3 J/K

Given reaction:

Br2(l) → Br2(g)

ΔS = ∑n(products)S⁰(products) - ∑n(reactants)S⁰(reactants)

     = 1 mole* S°(Br2(g)) - 1 mole*S°(Br2(l))

     =  1 mole *245.5 J/mol-K - 1 mole*152.2 J/mol-K

     = 93.3 J/K

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer